log(6/11)^5 how do you expand that
5 log ( 6 / 11 ) = 5 ( log6 - log11 ) = 5 [ log(2 3) - log11] = 5 * (log2 + log3 - log11 ).
We know that C log a = log a^C. We know that log (x/y) = log x - log yWe know that log xy = log x + log yTherefore... log(6/11)^5 =5 * log (6/11). Which can be expanded to...5 (log 6 - log 11) ... 5 (log 3 + log 2 - log 11)Its a law of logarithms.
