Verified Answer :

Willchemistry

Mole ratio:

2 H2 + O2 =  2 H2O

2 mol H2 ---------- 1 mol O2
1.67 mol H2 ------ ??

1.67 x 1 / 2 => 0.835 moles of O2

Answer : The number of moles of \(O_2\) required are 0.835 moles.

Explanation : Given,

Moles of \(H_2\) = 1.67 moles

The given balanced chemical reaction is,

\(2H_2+O_2\rightarrow 2H_2O\)

By the stoichiometry we can say that, 2 moles of hydrogen gas react with 1 mole of oxygen gas to give 2 moles of water as a product.

From the balanced reaction we conclude that,

As, 2 moles of \(H_2\) react with 1 mole of \(O_2\)

So, 1.67 moles of \(H_2\) react with \(\frac{1.67}{2}=0.835\) mole of \(O_2\)

Therefore, the number of moles of \(O_2\) required are 0.835 moles.

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