Verified Answer :

TSO

\(Slope = \frac{y_2 -y_1}{x_2-x_1}\) where the points are (x₁, y₁) and (x₂, y₂).

So, plugging in the points we were given
\(Slope = \frac{0 -(-10)}{-4-0} = \frac{10}{-4} = \boxed{\bf{-\frac{5}{2}}}\)

The slope is -5/2.

CharlieBrown2002

Hi there! :)

Step-by-step explanation:

\(SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}\)

\(\frac{0-(-10)}{(-4)-0}=\frac{10}{-4}=\frac{10/2}{-4/2}=\frac{5}{-2}=-\frac{5}{2}\)

Slope is -5/2

Final answer is -5/2

Hope this helps!

Thanks!

Have a nice day! :)

:D


Related Questions