in diagram, what is AC?
in diagram, what is AC?
you can use Pythagorean theory on this one a^2+b^2+c^2
so
first you need to find DB
a^2+8^2=17^2
a^2=225
a=15
next you need AD which can be found by subtracting DB from AB
so 21-15=6 AB=6
then we use Pythagorean again this time on the smaller triangle
6^2+8^2=c^2 c^2 is AC
36+64=c^2
100=c^2
10=c
AC=10
Answer:
AC = 10 units
Step-by-step explanation:
In the given right angle triangle BCD
\(BC^{2}=BD^{2}+CD^{2}\)
By putting BC = 17 and CD = 8
\(17^{2}= BD^{2}+8^{2}\)
\(BD^{2}=17^{2}-8^{2}=289-64\)
\(BD^{2}=225\)
\(BD=\sqrt{225}=15\)
Now in ΔACD
\(AC^{2}=AD^{2}+CD^{2}\)
\(AC^{2}=(AB-DB)^{2}+CD^{2}\) [since AD = AB-DB]
\(=(21-15)^{2}+8^{2}\)
\(=6^{2}+8^{2}\)
= 36 + 64
= 100
\(AC=\sqrt{100}=10units\)