Verified Answer :

meerkat18

we are given the equation 9y = 4x2 and is asked in teh problem the constant of variation for the quadratic equation. In this case, the standard form is y = kx2 where k is the constant of variation. Hence we divide the equation by 9 such that k is equal to 4/9

Answer:

option B is correct

The constant of variation is, \(k=\frac{4}{9}\).

Step-by-step explanation:

Since the quadratic variation is the relationship between the variables x and y

i.e, \(y=kx^2\); where k is the quadratic variation.

Given quadratic equation: \(9y=4x^2\)    ...[1]

Division property of equality states that you divide the same number to both sides of an equation

Divide both side by 9,we get

\(\frac{9y}{9}= \frac{4}{9}x^2\)

On simplifying we get;

\(y= \frac{4}{9}x^2\)

Now, compare above equation by equation[1] we get the value of k;

i.e, \(k=\frac{4}{9}\)

Therefore, the constant of variation is, \(k=\frac{4}{9}\).

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