The length of each side of a square is 3in more than the length of each side of a smaller square.
let the length of smaller square=x
the length of big square=x+3
The sum of the areas of the squares is 149in^2.
so x^2+(x+3)^2=149
or x^2+x^2+6x+9=149
or 2x^2+6x=149-9=140
