Answer:
1)
3 , -10
2)
10x + y
3)
2x-3y
Step-by-step explanation:
Ques 1)
We are given an algebraic expression as:
\(11x^2-12x-10\)
The following expression has three terms:
\(11x^2,-12x\ and\ -10\)
and the constant term is the term in which the variable is of exponent 0.
Hence, here we have the constant term as: \(-10\)
Ques 2)
We are given a expression in terms of x and y by:
\(7x+3x+2y-y\)
when on simplifying this expression we have:
\(=(7+3)x+(2-1)y\\\\=10x+y\)
Ques 3)
The expression is given by:
\(\dfrac{1}{2}(4x-6y)\)
On using the distributive property i.e.
\(a(b+c)=a\cdot b+a\cdot c\)
we have:
\(\dfrac{1}{2}(4x-6y)=\dfrac{1}{2}\times 4x+\dfrac{1}{2}\times (-6y)\\\\i.e.\\\\\dfrac{1}{2}(4x-6y)=2x-3y\)
