Answer:
Option A
Step-by-step explanation:
Given is a graph of a region on the left of the line including the line.
First let us find the equation of the line.
From the graph we find that the line passes through (0,1) and (1,-2)
Using two point formula for straight lines
\(\frac{y-y_{1} }{y_{2}-y_{1} } =\frac{x-x_{1} }{x_{2}-x_{1} }\)
Substitute to get
\(\frac{y-1}{-3} =\frac{x}{1} \\y-1=-3x\\y =1-3x\)
Consider origin and subtitute (0,0)
0 <=1
Hence the left side of the line which contains origin is the feasible region
Hence equation is
\(y\leq 1-3x\)
So option A is the right answer
