a copper wire ( density = 8.96 g/cm^3 ) has a diameter of 0.25 mm. if a sample of this copper wire has a mass of 22 g, how long is the wire?
V = πr²H
r = 0,25mm / 2 = 0,125mm = 0,0125cm
d = 8,96 g/cm³
m = 22g
\(d=\frac{m}{V}\\\\
\pi r^{2}H=\frac{m}{d}\\\\
H=\frac{m}{\pi r^{2}d}=\frac{22g}{\pi *(0,0125cm)^{2}*8,96\frac{g}{cm^{3}}}=\frac{22g}{3,14*0,00015625cm^{2}8,96\frac{g}{cm^{3}}}=\\\\\\\approx5004,55cm=50,0455m\)
Answer:
The length of the copper wire is 50.02 meters.
Explanation:
It is given that,
Density of the copper wire, \(d=8.96\ g/cm^3=8960\ kg/m^3\)
Diameter of copper wire, d = 0.25 mm = 0.00025 m
Radius of the copper wire, r = 0.000125 m
Mass of the copper, m = 22 g = 0.022 kg
We need to find the length of the wire. Let l is the length of the wire. The density of a copper wire is given by :
\(d=\dfrac{m}{V}\)
V is the volume of copper wire
\(d=\dfrac{m}{\pi r^2h}\)
\(h=\dfrac{m}{d\pi r^2}\)
\(h=\dfrac{0.022\ kg}{8960\ kg/m^3\times \pi (0.000125\ m)^2}\)
h = 50.02 m
So, the length of the wire is 50.02 meters. Hence, this is the required solution.