lynne walks dogs everyday to earn money. the fees she charges per month are 1 dog $40, 2 dogs $37.25, 3 dogs $34.50 each, 4 dogs $31.75 each. a pet store wants her to walk 8 dogs. if the pattern continues, how much will lynne charge to walk each of the 8 dogs?
1 dog = $40
2 dogs = $37.25
3 dogs = $34.50
4 dogs = $31.75
5 dogs = $29
6 dogs = $26.25
7 dogs = $23.50
8 dogs = $20.75
Pattern is minus $2.75
Answer: $20.75
Step-by-step explanation:
Given : Lynne walks dogs everyday to earn money.
The fees she charges per month are 1 dog $40 each , 2 dogs $37.25 each, 3 dogs, $34.50 each and 4 dogs $31.75 each.
let x be the number of dogs and f(x) be fee she charged per month.
We know that, the rate of change of f(x), if pattern continues
@@MATH_TOKEN_0@@
Thus she decreases her fee $2.75 per on increment of number of dogs
For x=8 , to find f(8), we consider same pattern to 8 dogs.
Thus,
\(\frac{f(8)-f(1)}{8-1}=-\$2.75\\\Rightarrow\frac{f(8)-40}{7}=-2.75\\\Rightarrow\ f(8)-40=7\times-2.75\\\Rightarrow\ f(8)-40=-19.25\\\Rightarrow\ f(8)=40-1925=\$20.75\)