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Dave sold 40 tickets for a concert. He sold X tickets at 2$ each and Y tickets at 3$ each. He collected 88$. Write down two equations connecting X and Y. Solve these two equations to find how many of each kind of ticket he sold

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apologiabiology

total value=88=totalvalueoftickets
88=2x+3y
total tickets s 40
x+y=40

we hae
88=2x+3y
40=x+y

eliminate
times second equation by -2 and add to first equation to eliminate x

88=2x+3y
-80=-2x-2y +
8=0x+1y

8=y
sub

x+y=40
x+8=40
minus 8
x=32

he sold 32 x tickets
sold 8  y tickets

For total ticket equation use the given: X+Y=40 then, for second equation on prices 2X+3Y=88

So the equations are:

X+Y=40 and 2X+3Y=88

To solve:

take first equation and place x by itself X=(40-Y) then take the equation and place them together:

2(40-Y)+3Y=88 then Foil;

(80-2Y)+3Y=88 Now combine like terms;

3Y-2Y=88-80 ---> Y=8 after place Y=8 in first equation;

X+Y=40 ---> X+8=40 ---> X=32

So the answers are:                                                                                                                       X=32 and Y=8

A little more than you asked but hope this helps :)

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