A 230 g sample of a compound contains 136.6 g of carbon, 26.4 g of hydrogen, and 31.8 g of nitrogen. The rest is oxygen. What is the mass percent of oxygen in the compound
mass of oxygen = 230g - (136,6g + 26,4g + 31,8g) = 35,2g
If 230g ---- is ----- 100%
so
35,2g ---- is ------ %O
%O = (35,2g*100%) / 230g = 15,3%
Answer: The mass percent of oxygen in given compound is 15.30%.
Explanation:
We are given:
Mass of nitrogen in compound = 31.8 g
Mass of hydrogen in compound = 26.4 g
Mass of carbon in compound = 136.6 g
Total mass of compound = 230 g
So, mass of oxygen will be = \(230-(136.6+26.4+31.8)=35.2g\)
To calculate the percentage composition of element in a compound, we use the following equation:
\(\% \text{composition}=\frac{\text{Mass of the element}}{\text{Mass of the compound}}\times 100\)
Putting values in above equation, we get:
\(\% \text{composition of oxygen}=\frac{35.2g}{230g}\times 100=15.30\%\)
Hence, the mass percent of oxygen in given compound is 15.30%.