Line AB contains points A (−1, 3) and B (5, 3). Line AB has a slope that is
slope between 2 points, (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1)
(-1,3) and (5,3)
x1=-1
y1=3
x2=5
y2=3
slope=(3-3)/(5-(-1))=0/(5+1)=0/6=0
slope is 0
Answer:
Slope of AB is 0.
Step-by-step explanation:
We have been given a line AB that has A(-1,3) and B(5,3)
We have a formula for slopw:
\(Slope=\frac{y_2-y_1}{x_2-x_1}\)
Here,\(x_1=-1,x_2=5,y_1=3,y_2=3\)
On substituting the values in the formula we get:
\(slope=\frac{3-3}{5-(-1)}\)
\(\Rightarrow slope=\frac{0}{6}\)
\(\Rightarrow slope=0\)
Hence, the required slope is: 0.