Answer:
A. \((x-5)^2+(y-1)^2=0\)
Step-by-step explanation:
When the radius of a circle is zero, then it is called a degenerate circle.
The general equation of circle with center at \((h,k)\) and radius of r is,
\((x-h)^2+(y-k)^2=r^2\)
So the radius is 0, so the equation will be in form of,
\((x-h)^2+(y-k)^2=0\)
Out of the given option A has is a circle with radius of 0.
\((x-5)^2+(y-1)^2=0^2\)
