Answer
Find out the three pairs for possible values for a and b .
To prove
As given
\(The\ product\ of\ two\ positive\ fractions\ a\ and\ b\ is\ \frac{15}{56} .\)
i.e it is written in the form.
\(a\times b = \frac{15}{56}\)
When
\(a = \frac{3}{2} , b = \frac{5}{28}\)
Than
\(\frac{3\times 5}{2\times 28} = \frac{15}{56}\)
When
\(a = \frac{3}{4} , b = \frac{5}{14}\)
Than
\(\frac{3\times 5}{4\times 14} = \frac{15}{56}\)
When
\(a = \frac{1}{2} , b = \frac{15}{28}\)
Than
\(\frac{1\times 15}{2\times 28} = \frac{15}{56}\)
Hence proved
