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\(pH=-log|H_{3}O^{+}|\\\\ pH=-log2.4*10^{-5}=-(log2.4+log10^{-5})=-(0,38-5)=-(-4.62)\\\\ pH=4.62\)

Answer:

The pH of the solution is 4.61.

Explanation:

The pH of the solution is defined as negative logarithm of \(H_3O^+\) ion concentration.

\(pH=-\log[H_3O^+]\)

The concentration of \(H_3O^+=2.4\times 10^{-5} molar\)

\(pH=-\log[2.4\times 10^{-5} M]=4.61\)

The pH of the solution is 4.61.

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