\(y-4=\dfrac{1}{4}(x-8)\)
The slope-intercept form: \(y=mx+b\)
m - a slope
b - y-intercept (0; b)
The point-slope form: \(y-y_0=m(x-x_0)\)
therefore \(m=\dfrac{1}{4}\)
We have a point (0; 2) ⇒ it's the y-intercept, therefore \(b=2\)
Answer: \(C)\ y=\dfrac{1}{4}x+2\)
Other method:
\(y-4=\dfrac{1}{4}(x-8)\ \ \ \ \ |use\ distributive\ property:\ a(b-c)=ab-ac\\\\y-4=\dfrac{1}{4}x-2\ \ \ \ \ \ |add\ 4\ to\ both\ sides\\\\y=\dfrac{1}{4}x+2\)
