Answer: -1
Step-by-step explanation:
The given function : \(f(p) = p^2 + 3p + 1\)
To find : The value of the given function ( \(f(p) = p^2 + 3p + 1\)) at p =-2.
We substitute the value of p=-2 in the given function, we get
\(f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1\)
Therefore , the value of the given function at p=-2 = -1
