three pigs entered a race around a track. piggly takes 6 minutes to run one lap. piglet takes 3 minutes to run one lap and it takes wiggly 5 minutes to run one lap. if all three pigs begin the race at the same time, how many minutes will it take for all three pigs to be at the starting point

6 minutes, 3 minutes, 5 minutes
we need to find the lowest common multiple of these numbers.

6 : 6,12,18,24,30
3: 3,6,9,12,15,18,21,24,27,30
5: 5,10,15,20,25,30

30 is ur lowest common multiple...so they will all meet at the starting point in 30 minutes...hooray for piggly, piglet, and wiggly :)

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AFOKE88 AFOKE88 · Answer 2 · 2021-10-21T06:08:55-04:00

The number of minutes it will take for all three pigs to be at the starting point is; 30 minutes

Number of pigs in the race = 3 pigs

Time for pigly to run one lap = 6 minutes

Time for piglet to run one lap = 3 minutes

Time for Wiggly to run one lap = 5 minutes

We want to find the time in which the 3 pigs will meet again at the starting point. This simply means we have to find the LCM which is the least common multiple of 6, 3 and 5 minutes.

Factors of 6 = 1, 2, 3, 6

Factors of 3 = 1, 3

Factors of 5 = 1, 5

Thus;

LCM = 2 × 3 × 5

LCM = 30

Thus, in conclusion the 3 pigs will be at the starting point again after 30 minutes.

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