Verified Answer :
Answer:
Yes, JK and LN have the same midpoint
Step-by-step explanation:
In order to demonstrate that JK and LN have the same midpoint, we have to find their midpoints
The coordinates of the midpoint of a segment are:
\(\frac{x_{1}+ x_{2}}{2}, \frac{y_{1}+ y_{2}}{2}\)
Where \(x_{1},y_{1}\) are the coordinates of the initial point and \(x_{2},y_{2}\) the coordinates of the endpoint
Step 1: Find the JK's midpoint
For this segment:
J(-2,3); then \(x_{1}=-2\) and \(y_{1}=3\)
K(6,5); then \(x_{2}=6\) and \(y_{2}=5\)
The coordinates of the midpoint are:
\(\frac{x_{1}+ x_{2}}{2}, \frac{y_{1}+ y_{2}}{2}=\frac{-2+6}{2}, \frac{3+5}{2}=2,4\)
Step 2: Find the LN's midpoint
For this segment:
L(0,7); then \(x_{1}=0\) and \(y_{1}=7\)
N(4,1); then \(x_{2}=4\) and \(y_{2}=1\)
The coordinates of the midpoint are:
\(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}=\frac{0+4}{2}, \frac{7+1}{2}=2,4\)
Therefore JK's Midpoint and LN's Midpoint are the same
The mid-point of the given lines is (2,4)
The given end points:
\(J = (-2, 3) \ \ and \ \ K = (6,5)\\\\I = (0,7) \ \ \ and \ \ N = (4,1)\)
To find:
The midpoint of the lines
The midpoint of a given line is calculated as:
\(mid-point = \frac{x_1 + x_2}{2} , \ \frac{y_1 + y_2}{2}\)
The mid-point of JK is calculated as:
\(mid-point \ JK = (\frac{-2 + 6}{2}, \ \frac{3+ 5}{2} ) = (\frac{4}{2} , \frac{8}{2} ) = (2,4)\)
The mid-point of IN is calculated as:
\(mid-point \ IN = (\frac{0 + 4}{2}, \ \frac{7+ 1}{2} ) = (\frac{4}{2} , \frac{8}{2} ) = (2,4)\)
Thus, the mid-point of the given lines is (2,4)
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