Explanation:
As molar mass of \(N_{2}O\) is 44.013 g/mol and it is given that its mass is 0.195 g.
Therefore, calculate its number of moles as follows.
No. of moles = \(\frac{mass}{\text{molar mass}}\)
= \(\frac{0.195 g}{44.013 g/mol}\)
= 0.0044 mol
Here, in 1 mole of \(N_{2}O\) there is 2 mole of N. Thus, moles of N present in it is calculated as follows.
\(2 \times 0.0044 mol\)
= 0.0088 mol
Thus, we can conclude that in 0.195 g of \(N_{2}O\) there are 0.0088 mol of N.
