How do you factor 3x^2+7x-6=0 and solve?
Do the factoring method(3x-2)(x+3)3x=2 X=-3x=2/3if we check3x2+7x=63(2/3)2+7(2/3)=64/3+14/3=618/3=6The x=2/3 is correct now lets see the x=-33x2+7x=63(-3)2+7(-3)=63(9)-21=627-21=66=6so both x can be used in factoring
Answer: x2=-3
Step-by-step explanation: