\(x-5y=2\)
Hence \(x=2+5y\) (Equation I)
\(9x+8=15\) (Equation II)
Substituting Equation I in Equation II
\(9(2+5y)+8=15\)
\(18+45y+8=15\)
\(26+45y=15\)
\(45y=-11\)
Hence \(y= - \frac{11}{45}\)
Substituting this in Equation in I to get X
\(x-5(- \frac{11}{45} )=2\)
\(x+ \frac{11}{9}=2\)
\(x= 2- \frac{11}{9}\)
\(x= \frac{17}{9}\)
