3/5y+a=b, solve for y
y=-5a+5b/3 Thats what I got.
\(\frac{3}{5}\)y + a = b Subtract a from both sides\(\frac{3}{5}\)y = b - a Multiply both sides by \(\frac{5}{3}\) to cancel out the fractiony = \(\frac{5b - 5a)}{3}\)
