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When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, how many grams of nitrogen gas are produced?

4NH3(g)+3O2(g)--->2N2(g)+6H2O(g)

Verified Answer :

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NH₃:

N = 810²²
NA = 6.0210²³

n = N/NA = 810²²/6.0210²³ ≈ 1.3310⁻¹=0.133mol

O₂:

N=710²²
NA = 6.0210²³

n = N/NA = 710²²/6.0210²³ = 1.1610⁻¹=0.116mol

4NH₃                   +                        3O₂                      ⇒          2N₂ + 6H₂O
4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = nM = 0.0665mol28g/mol = 1,862g

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