Jay0304
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Mr. Rodriguez invests half his money in land, a tenth in stocks, and. A twentieth in bonds. He puts the remaining $35,000 in his saving account. What is the total amount of money that Mr. Rodriguez saves and invests.

Verified Answer :

daguealex

1/2- 10/20
1/10- 2/20
1/20- 1/20
So $35,000 is 7/20 of his money
Then divide 35000/(7/20) to get 100,000 as what he saves

Answer:

Mr. Rodriguez saves and invests $65,000.

Step-by-step explanation:

Let Mr. Rodriguez has total money = $x

Now his investment in land = \(\frac{x}{2}\)

Investment in stocks =\(\frac{x}{10}\)

Investment in bonds =\(\frac{x}{20}\)

So total investment =\(\frac{x}{2}\)+\(\frac{x}{10}\)+\(\frac{x}{20}\)

                                  =  \(\frac{10x+2x+x}{20}\)

                                 =  \(\frac{13x}{20}\)

Remaining amount after investment is $35,000

So 35,000 = x -  @@MATH_TOKEN_8@@

     35,000 =  @@MATH_TOKEN_9@@

             7x  = 20 × 35,000

             7x = 700,000

               x = @@MATH_TOKEN_10@@

               x = $100,000

and investments =  \(\frac{13x}{20}\) =  \(\frac{13\times100,000}{20}\) = $65,000

Total amount of money that Mr. Rodriguez saves $65,000.

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