A local Walmart sells sweatpants ($7) and jackets ($14). If total sales were $6,160 and customers bought 8 times as many sweatpants as jackets, what would be the number of jackets sold?
let j be jackets and s be sweatpants
8j=s
7j+14s=6160
Bracket the two together with (
substitute:
7(8j)+14j=6160
56j+14j=6160
70j=6160
j=6160/70
j=88
go back to the first equation
8(88)=s
704=s
Final answer: 704 sweatpants, 88 jackets
Answer:
88
Step-by-step explanation:
Given: local Walmart sells sweatpants $7 and jackets $14.
To Find: If total sales were $6,160 and customers bought 8 times as many sweatpants as jackets find the number of jackets sold.
Solution:
Let the number of jacket sold be \(=\text{j}\)
Price of one jacket \(=\$14\)
Let the number of sweatpants sold be \(=\text{s}\)
Price of one sweatpant \(=\$7\)
Now,
equation for total sales is
\(\text{total sales}\) \(=14\text{j}+7\text{s}\)
as customers bought 8 times as many sweatpants as jackets,
\(\text{s}=8\times\text{j}\)
and Total sales\(=\$6160\)
Putting in equation
\(6160=14(\text{j})+7\times8\text{j}\)
\(6160=70\text{j}\)
\(\text{j}=88\)
Therefore the number of jacket sold is \(88\)