Simplify 3 over quantity of 5 minus 6 i
\(\frac{3}{5-6i}=\frac{3}{5-6i}\times\frac{5+6i}{5+6i}\\=\frac{3(5+6i)}{(5-6i)(5+6i)}=\frac{15+18i}{25+36}\\=\frac{15+18i}{61}\)