11-1/2y=3+6x I need help solving
11 - \(\frac{1}{2}\)y = 3 + 6x Subtract 11 from both sides
-\(\frac{1}{2}\)y = 3 + 6x - 11 Combine like terms (3 and -11)
-\(\frac{1}{2}\)y = 6x - 8 Multiply both sides by -2 to cancel out the fraction
y = -12x + 16
Answer:
\(y=-12x+16\)
Step-by-step explanation:
We have been given an equation \(11-\frac{1}{2}y=3+6x\). We are asked to solve our given equation for y.
Subtract 11 from both sides:
\(11-11-\frac{1}{2}y=3-11+6x\)
\(-\frac{1}{2}y=-8+6x\)
Multiply both sides by -2:
\((-2)-\frac{1}{2}y=-2(-8+6x)\)
\(y=(-2)(-8)+(-2)(6x)\)
\(y=16-12x\)
\(y=-12x+16\)
Therefore, our required equation would be \(y=-12x+16\).