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Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?


y – 12 = –5(x + 2)

y – 12 = 2(x + 2)

y + 12 = 2(x – 2)

y + 12 = –5(x – 2)

Verified Answer :

texaschic101

f(x) = -5x + 2...this can be changed to y = -5x + 2...so ur slope(m) = -5

point-slope form : y - y1 = m(x - x1)
slope(m) = -5
(-2,12)...x1 = -2 and y1 = 12
now we sub
y - 12 = -5(x -(-2) =
y - 12 = -5(x + 2) <====

dalendrk

The point-slope form: \(y-y_0=m(x-x_0)\)

The slope0intercept form: \(y=mx+b\)

\(f(x)=-5x+2\Rightarrow m=-5\)

\((-2;\ 12)\Rightarrow x_0=-2;\ y_0=12\)

subtitute:

\(y-12=-5[x-(-2)]\to\boxed{y-12=-5(x+2)}\)

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