Answer: B. \((x-3)^2+(y+2)^2=9\)
Step-by-step explanation:
From the given graph, it can be seen that the center of circle lies at (3,-2).
Radius = distance from the center to the boundary of circle.
=|3-0|=3 units
Standard equation of circle :
\((x-h)^2+(y-k)^2=r^2\), where (h,k) is center and r is the radius of the circle.
Then , standard equation of the circle in the graph (having center (3,-2) and radius = 3 units)
\((x-3)^2+(y-(-2))^2=(3)^2\)
\((x-3)^2+(y+2)^2=9\)
