what is the volume of a pyramid 5 feet tall if its base is a square 4 feet by 4 feet
Given:
height (h) = 5 feet
base length (l) = 4 feet
base width (w) = 4 feet
Now,
Volume of a pyramid = \(\frac{l*w*h}{3}\)
= \(\frac{5*4*4}{3}\)
= \(\frac{80}{3}\)
= \(26.67 ~ ft^{3}\) ----> rounded to the nearest hundredth
V = (1/3) Base Area height.
= (1/3) (44) * 5 = 80/3 cubic feet.
= 26. 6667 cubic feet.