1 Find the surface area of the cylinder
we know that
the surface area of a cylinder is equal to
\(SA=2*area\ of\ the\ base +perimeter\ of\ the\ base*height\)
\(area\ of\ the\ base= \pi* r^{2}\)
\(perimeter\ of\ the\ base= 2*\pi* r\)
\(height=r\)
Substitute
\(SA=2*\pi*r^{2} +2*\pi*r*r\)
\(SA=4*\pi *r^{2}\)
2 Find the surface area of the cone
we know that
the surface area of a cone is equal to
\(SA=\pi*r^{2}+\pi *r*l\)
\(SA=\pi *r^{2}+\pi *r*2*r\)
\(SA=3* \pi *r^{2}\)
3 Compare the surface area of the cylinder with the surface area of the cone
\(4 \pi r^{2}
eq 3 \pi r^{2}\)
therefore
the answer is
False
