The sum of 3 sixteens and 2 nines
\(\frac{3}{16} + \frac{2}{9}\)
find a common factor that can make the denominators (bottom number) the same number. In this case, that number is 144 (denominators multiplied (9 x 16) )
Multiple each side to get the denominator to equal 144.
\(\frac{3}{16} \frac{(9)}{(9)} = \frac{27}{144} \\ \\ \frac{2}{9} \frac{(16)}{(16)} = \frac{32}{144}\)
\(\frac{27}{144} + \frac{32}{144} = \frac{59}{144}\)
The sum is \(\frac{59}{144}\)