10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.
10x-35+3ax=5ax-7a
10x-35=5ax-7a-3ax
10x-35=a(5x-7-3x)
(10x-35)/(5x-7-3x)=a
therefore a=(10x-35)/(5x-7-3x)
Answer:
\(a=\frac{10x-35}{2x-7}\)
Step-by-step explanation:
We have been given an equation \(10x-35+3ax=5ax-7a\). We are asked to solve the given equation for 'a'.
Switch sides:
\(5ax-7a=10x-35+3ax\)
\(5ax-3ax-7a=10x-35+3ax-3ax\)
\(2ax-7a=10x-35\)
Factor out a:
\(a(2x-7)=10x-35\)
Divide both sides by \((2x-7)\):
\(\frac{a(2x-7)}{(2x-7)}=\frac{10x-35}{(2x-7)}\)
\(a=\frac{10x-35}{2x-7}\)
Therefore, our required equation would be \(a=\frac{10x-35}{2x-7}\).