Verified Answer :

Yipes

\(m=337,1g\\ M_{HBr}=81\frac{g}{mol} \ \ \Rightarrow \ \ n=\frac{m}{M}=\frac{337,1g}{81\frac{g}{mol}}=4,2mol\)

If  2,41kJ   --- require ----- 1mol
                          so
       Q       ---- require ----- 4,2mol

\(Q=\frac{4,2mol*2,41kJ}{1mol}=10,122kJ\)

The heat energy required is \(10.12kJ\).

Heat of fusion :

The molar heat capacity of a chemical substance is the amount of energy that must be added, in the form of heat, to one mole of the substance

Given that, the molar mass of \(HBr\) is \(337.1g\)

  • Atomic mass of \(HBr\) \(=81g/mol\)
  • Number of mole \(=\frac{337.1}{81}=4.2mol\)
  • The molar heat of fusion of \(HBr\) is \(2.41 kJ/mol.\)

It means that,

\(1\) mol of\(HBr\) require \(=2.41kJ\) heat energy

\(4.2\) mol of \(HBr\) require \(=2.41*4.2=10.12kJ\) heat energy

Learn more about the heat energy here:

https://brainly.com/question/19666326

Related Questions