For this case we have a function of the form:
\(y = A * (b) ^ x
\)
Where,
A: initial value
b: growth rate
x: time in months
Rewriting the equation we have:
\(y = 250 * (2) ^ {(\frac{1}{6} * x)}
\)
When 2 years pass, we have 24 months.
Therefore, substituting the value of x = 24 in the given equation we have:
\(y = 250 * (2) ^ {(\frac{1}{6} * 24)}
y = 4000
\)
Answer:
there will be 4000 crickets after 2 years
