What are the possible number of positive real, negative real, and complex zeros of

f(x) = –7x4 – 12x3 + 9x2 – 17x + 3?

Answer:


A)Positive Real: 1

Negative Real: 3 or 1

Complex: 2 or 0


B)Positive Real: 3 or 1

Negative Real: 2 or 0

Complex: 1


C)Positive Real: 3 or 1

Negative Real: 1

Complex: 2 or 0


D)Positive Real: 4, 2 or 0

Negative Real: 1

Complex: 0 or 1 or 3

Verified Answer :

f(x) = −7x^4 − 12x^3 + 9x^2 − 17x + 3 you will have to change the signs so,

f(−x) = −7x^4 + 12x^3 + 9x^2 + 17x + 3


For positive roots, count number of times coefficients of f(x) change sign:

− − + − +

3 times -----> 3 or 1 positive roots


For negative roots, count number of times coefficients of f(−x) change sign:

− + + + +

1 time -----> 1 negative root


Positive real: 3 or 1

Negative real: 1

Complex non-real: 0 or 2

The answer is C

The answer is C :)
It can be properly explained by others below or above me