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Consider the curves in the first quadrant that have equations y=Aexp(6x) where A is a positive constant. Different values of A give different curves. The curves form a family, F. Give a formula g(y) for the slope at (xy) of the member of F that goes through (xy). The formula should not involve A or x.

Verified Answer :

then the derivative of
Ae6x is
6Ae6x replace x by
16ln(yA) and get
6y
i found this somewhere else i didnt do the work but i believe its right

Answer:

\(y'=6y\)

Step-by-step explanation:

Given is the curve exponential in the I quadrant

\(y=Ae^{6x}\)

where A is positive

For different values of A, we have different curves which together form a family of curves

The differential equation to be formed using slope and x,y would be as follows:

Differentiate the given equation wrt x

\(y' =6Ae^{6x}\)

This is the slope

Eliminate A to get

slope =

\(y'=6y\)

This would be the formula for slope without A or x in it

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