The answer is 10%
The percent error is used to determine the precision of calculations. It can be expressed as:
\(e = \frac{v-v_{1} }{v_1} *100\)
where:
e - the percent error,
v - experimental value (measured value),
v₁ - theoretical value,
It is given:
e = ?
v = 88 calories
v₁ = 80 calories
Thus, the percent error is:
\(e = \frac{88-80}{80}*100 = \frac{8}{80}*100=0.1*100=10%\)
