When the gases dihydrogen sulfide and oxygen react, they form the gases sulfur dioxide and water vapor. (How would this be written in an equation?)
When the gases dihydrogen sulfide and oxygen react, they form the gases sulfur dioxide and water vapor. so the balanced equation is
2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(l)
hope it helps
Answer:
The balanced chemical equation can written be as:
\(2H_2S (g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O (g)\)
Explanation:
Dihydrogen sulfide = \(H_2S\)
Oxygen gas = \(O_2\)
Sulfur dioxide = \(SO_2\)
Water vapor =\(H_2O\)
The balanced chemical equation can written be as:
\(2H_2S (g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O (g)\)
According to reaction , 2 moles of hydrogen sulfide reacts with 3 moles of oxygen gas to give to 2 moles of sulfur dioxide and 2 moles of water vapors.