The correct answer is: c.)–6, 0, –4
This is due to the following:
f(x) = 0
\(x^{3}+10x^{2}+24x = 0\)
\(x · (x^{2} + 10x + 24) = 0\)
\(x^{2} + 10x - 24 = 0\)
\(x = \frac{- 10 +- \sqrt{10^{2}- 4 x 1 x 24}} {2}\)
\(x = \frac{- 10 + 2} {2} = -4\)
\(x = \frac{- 10 - 2} {2} = -6\)
\(x = -6\)
\(x = -4\)
\(x = 0\)
