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jordbGlaur7av4ela
jordbGlaur7av4ela jordbGlaur7av4ela
  • 05-09-2016
  • Mathematics
Answered

Find the limit as x approaches 0 of sin2x/4x.

Verified Answer :

HomertheGenius
HomertheGenius HomertheGenius
  • 13-09-2016

As we know that:
\(\lim_{n \to 0} \frac{sinn}{n}=1\)
\(\lim_{x \to 0} \frac{sin2x}{4x}: \frac{2}{2}= \\ \frac{1}{2} \lim_{x \to 0} \frac{sin2x}{2x} = \frac{1}{2}*1 = \frac{1}{2}\)

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