Verified Answer :

Willchemistry

HCl  ⇄   H⁺ + Cl⁻

pH = - log [ H⁺]

pH = - log [  2.75 x 10⁻⁵]

pH = 4.56

hope this helps!

antonsandiego

I am absolutely sure that the pH of an HCl solution if the [H+] can be founded by the formula I have attached below. Quite an easy one and that is the only thing you need. Hope you still need the answer because this one is truly helpful.


\(pH = -lo[H+] log (2.75x10^-5) = pH of HCl = 4\)

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