Verified Answer :

1 + cos t = ( √3 + 2 ) /2
cos t = ( √3 + 2 ) / 2 - 1
cos t = ( √3 + 2 - 2 ) / 2
cos t = √3/2
t 1 = π/6,  t 2 = 11π/6
Answer: C ) π/6,  11π/6.

Answer:

Option C is right

Step-by-step explanation:

\(1+cos\theta =\frac{\sqrt{3}+2 }{2} =\frac{\sqrt{3} }{2} +1\)

Now we cancel 1 and get

\(cos\theta =\frac{\sqrt{3} }{2}\)

The solutions would be positive for cos hence the angle lies in I quadrant, IV quadrant.

In I quadrant angle satisfying in the I quadrant, is 30 degrees, pi/6

In IV quadrant this would be 2pi-pi/6 = 11pi/6

Hence solution is

pi/6, 11 pi/6

OPtionC