Answer:
\(3.60~mol~SO_2\)
Explanation:
The first step is the conversion from Kg to g:
\(0.23~Kg~\frac{1000~g}{1~Kg} = 230~g~SO_2\)
Then we have to calculate the molar mass of \(SO_2\):
\(O=~16~g/mol\)
\(S=~32~g/mol\)
\(SO_2=~(16x2)*(32*1)=~64g/mol\)
\(1~mol~SO_2=~64~g~SO_2\)
With the molar mass is possible to calculate the moles:
\(230~g~SO_2\frac{1~mol~SO_2}{64~g~SO_2} = 3.60~mol~SO_2\)
