ok so easy peasy
remember exponential laws
dividing
\(\frac{x^m}{x^n}=x^{m-n}\)
also
(ab)/(cd)=(a/c)(b/d)
also
\(x^{-m}= \frac{1}{x^m}\)
so
\(\frac{pq^7r^0}{pq^7r} =( \frac{p^1}{p^1} )( \frac{q^7}{q^7} )( \frac{r^0}{r^1} )\)=(1)(1)\(( \frac{1}{r} )\)=\(\frac{1}{r}\)=\(r^{-1}\)
answer is \(r^{-1}\)
