How do i solve Sec^2x+2secx=0
Let sec x = asec^2 x + 2sec x = 0=> a^2 + 2a = 0=> a(a + 2) = 0=> a = 0 or a + 2 = 0a = -2i.e. sec x = -21/cos x = -2-2cos x = 1cos x = -1/2x = cos^(-1) (-1/2) = 2pi/3
Answer:
a on edge2020
Step-by-step explanation:
took the test and got it right