If the complex number x = 3 + bi and |x|^2 = 13, which is a possible value of b?

A2
B4
C9
D10

The correct answer is:

A) 2.

Explanation:

We know that |x|² = 13 and x = 3+bi:

(3+bi)² = 13
3² + b² = 13
9 + b² = 13

Subtract 9 from each side:
9 + b² - 9 = 13 - 9
b² = 4

Take the square root of each side:
√b² = √4
b = 2

Answer Link

okpalawalter8 okpalawalter8 · Answer 2 · 2022-07-07T06:09:03-04:00

okpalawalter8 okpalawalter8

07-07-2022

A possible value of b is mathematically given as

b = 2

What is a possible value of b ?

Generally, the equation for the complex number is mathematically given as

x = 3 + bi and |x|^2 = 13,

Therefore

\((3+bi)^2 = 13\\\\9 + b^2 = 13\\\\b^2 = 4\)

Take the square root of each side:

\(\sqrt{b^2} = \sqrt{4}\)

b = 2

In conclusion,

If the complex number x = 3 + bi and |x|^2 = 13, which is a possible value of b? A2B4C9D10

Verified Answer :

What is a possible value of b ?

Related Questions

If the complex number x = 3 + bi and |x|^2 = 13, which is a possible value of b?

A2
B4
C9
D10