Verified Answer :

\(11-\dfrac{1}{2}y=3+6x\ \ \ \ \ |subtract\ 11\ from\ both\ sides\\\\-\dfrac{1}{2}y=-8+6x\ \ \ \ \ |change\ signs\\\\\dfrac{1}{2}y=8-6x\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\y=4-3x\)

Answer:

The value of the provided equation for y is \(y=-12x+16\).

Step-by-step explanation:

Consider the provided equation.

\(11-\frac{1}{2}y=3+6x\)

We need to solve the above equation for y.

Subtract 11 from both the sides.

\(11-11-\frac{1}{2}y=3-11+6x\)

\(-\frac{1}{2}y=6x-8\)

Multiply both the sides by -2

\(-\frac{1}{2}y\times -2=-2(6x-8)\)

\(y=-12x+16\)

Hence, the value of the provided equation for y is \(y=-12x+16\).