Solve for y: 11-1/2y=3+6x
\(11-\dfrac{1}{2}y=3+6x\ \ \ \ \ |subtract\ 11\ from\ both\ sides\\\\-\dfrac{1}{2}y=-8+6x\ \ \ \ \ |change\ signs\\\\\dfrac{1}{2}y=8-6x\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\y=4-3x\)
Answer:
The value of the provided equation for y is \(y=-12x+16\).
Step-by-step explanation:
Consider the provided equation.
\(11-\frac{1}{2}y=3+6x\)
We need to solve the above equation for y.
Subtract 11 from both the sides.
\(11-11-\frac{1}{2}y=3-11+6x\)
\(-\frac{1}{2}y=6x-8\)
Multiply both the sides by -2
\(-\frac{1}{2}y\times -2=-2(6x-8)\)
\(y=-12x+16\)
Hence, the value of the provided equation for y is \(y=-12x+16\).